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^3-2.2Z^2+1.5Z-0.35=0
We add all the numbers together, and all the variables
-2.2Z^2+1.5Z=0
a = -2.2; b = 1.5; c = 0;
Δ = b2-4ac
Δ = 1.52-4·(-2.2)·0
Δ = 2.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$Z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.5)-\sqrt{2.25}}{2*-2.2}=\frac{-1.5-\sqrt{2.25}}{-4.4} $$Z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.5)+\sqrt{2.25}}{2*-2.2}=\frac{-1.5+\sqrt{2.25}}{-4.4} $
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